OpenSCAD User Manual's section on operators does not mention precedence. Quick Web searches found nothing. I assume the usual order of exponentiation, then multiplication, then addition does hold, but how does e.g. a conditional operator or unary minus interact with these? Is there an official document describing the precedence of operators in OpenSCAD?
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$\begingroup$ I'm not sure if/where it's documented but I think largely they follow C or C++ precedent for precedence. $\endgroup$– R.. GitHub STOP HELPING ICECommented Sep 28, 2021 at 2:12
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1$\begingroup$ If you aren't sure, use parenthesis to force precedence. $\endgroup$– 0scar ♦Commented Sep 28, 2021 at 11:39
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$\begingroup$ @0scar That's what I'm doing, but it would be nice to know. $\endgroup$– user31389Commented Sep 28, 2021 at 12:55
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1 Answer
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Within OpenSCAD expressions, the order of precedence is:
| Operators | Description |
|---|---|
| () [] | group, vector, or range |
| () [] . | function call, indexing, member lookup |
| ^ | exponentiation |
| ! + - | unary operations |
| * / % | multiplication |
| + - | addition |
| < <= >= > | ordering |
| == != | equality |
| && | logical AND |
| || | logical OR |
| ?: function() let() assert() echo() | ternary operator and unary pseudo-operators |
There are no bit-wise operators, and neither comma nor "=" are operators.
Source: openscad/src/parser.y
